F(x)=2x^2-32x+560

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Solution for F(x)=2x^2-32x+560 equation: 



(F)=2F^2-32F+560

We move all terms to the left:

(F)-(2F^2-32F+560)=0

We get rid of parentheses

-2F^2+F+32F-560=0

We add all the numbers together, and all the variables

-2F^2+33F-560=0

a = -2; b = 33; c = -560;
Δ = b2-4ac
Δ = 332-4·(-2)·(-560)
Δ = -3391
Delta is less than zero, so there is no solution for the equation

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